Asked by Albert
A 5 meter, 100 N/m spring is at a 30 degree angle to the horizontal. If a 10 kg weight is placed on the spring when it is compressed 2 meters, how high will it travel?
Answers
Answered by
drwls
The initial stored potential energy in the spring,
(1/2) k X^2,
is initial converted to 3/4 (cos 30)^2 kinetic energy of horizontal motion and 1/4 (sin 30)^2 kinetic energy of vertical motion. That means (1/8) k X^2 is available to be converted to potential energy. That tells you how far it will rise above the initially compressed position. The length of the spring doesn't matter here.
(1/2) k X^2,
is initial converted to 3/4 (cos 30)^2 kinetic energy of horizontal motion and 1/4 (sin 30)^2 kinetic energy of vertical motion. That means (1/8) k X^2 is available to be converted to potential energy. That tells you how far it will rise above the initially compressed position. The length of the spring doesn't matter here.
Answered by
Bertrand
How do you solve for the weight's maximum height above the ground?
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