Asked by Lucifer
A room measures 6m by 8m to the nearest meter. A carpet tile measures 50cm exactly. What is the maximum number of carpets tiles that need to be bought to cover the floor of the rectangular room?
Answers
Answered by
b vikram
600*800=4800cm
4800/50=96
4800/50=96
Answered by
Reiny
600 cm x 800 cm = 480000 cm^2, not 4800 cm
each tile covers 2500 cm^2
number of tiles = 480000/2500
= 192
or
you can lay 12 tiles along the 6 m side
and 16 tiles along the 8 m side
number of tiles = 12x16 or 192
each tile covers 2500 cm^2
number of tiles = 480000/2500
= 192
or
you can lay 12 tiles along the 6 m side
and 16 tiles along the 8 m side
number of tiles = 12x16 or 192
Answered by
Teresa
UB 650x 850 =552500
50x 50=2500
552500/2500=221
50x 50=2500
552500/2500=221
Answered by
s
A room is 8 meter long and 6 meter wide.if floor is paved of square tiles then what should be the maximum size of the tile?sole it
Answered by
YeBoi
48m^2 boiiiii
Answered by
Uhm
upper bounds = 8.5m and 6.5m
Maximum = 8.5*6.5 = 55.25m^2
55.25m^2 = 552500cm^2
50*50 = 2500cm^2
552500/2500 = 221
maximum amount of carpet tiles = 221
Maximum = 8.5*6.5 = 55.25m^2
55.25m^2 = 552500cm^2
50*50 = 2500cm^2
552500/2500 = 221
maximum amount of carpet tiles = 221
Answered by
ronaldo
I don,t know show us how you did it
Answered by
Herald
idk
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.