Asked by Prince
a) The ship left the port and sailed for 2 hours on a course of 75O, at an average speed of 2.5 nautical miles per hour.
b)
North
It changed its course to 165O and travelled for 3 hours, at an average speed of 4 nautical miles per hour.
Your team is tasked to lead the rescue. You will be needing the following:
1. distance of the ship from the port
2. bearing from the port to the ship
b)
North
It changed its course to 165O and travelled for 3 hours, at an average speed of 4 nautical miles per hour.
Your team is tasked to lead the rescue. You will be needing the following:
1. distance of the ship from the port
2. bearing from the port to the ship
Answers
Answered by
Reiny
Assuming those directions are 75° and 165°.
and ignoring the
b)
North , whatever that means
you have a very simple problem.
I made a sketch with O the port, P as its first position and Q as its final position.
With some simple geometry you should see that angle P is a right angle, OP = 5 and PQ=12
so OQ^2 = 5^2+12^2
OQ = 13
in triangle OPQ,
tan O = 12/5
angle O = appr 67.4°
so the bearing from port i = (75+67.4)° = 142.4°
and ignoring the
b)
North , whatever that means
you have a very simple problem.
I made a sketch with O the port, P as its first position and Q as its final position.
With some simple geometry you should see that angle P is a right angle, OP = 5 and PQ=12
so OQ^2 = 5^2+12^2
OQ = 13
in triangle OPQ,
tan O = 12/5
angle O = appr 67.4°
so the bearing from port i = (75+67.4)° = 142.4°
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