a ship starts from port at a bearing of South 32 degrees East. It travels 8 miles in this direction before turning to a bearing of North 14 degrees East. It travels 15 miles in this direction, before finally turning to a bearing of South 72 degrees East and travels another 4 miles in this direction. How far is the ship from the port?
6 answers
I recommend doing this graphically.
I haven tried doing it graphically using the law of sines but am still unable to come up with a consistent answer. It is also asking what is the bearing of the ship to the port from the final point?
graphically is not the law of sines...
ok thanks for the help?
Given: AB = 8mi[148o]CW, BC = 15[14o], CD = 4[108o].
X = 8*sin148+15*sin14+4*sin108 = 11.7 miles.
Y = 8*cos148+15*cos14+4*cos108 = 6.5i miles.
D = 11.7 + 6.5i = 13.4mi[61] CW.
X = 8*sin148+15*sin14+4*sin108 = 11.7 miles.
Y = 8*cos148+15*cos14+4*cos108 = 6.5i miles.
D = 11.7 + 6.5i = 13.4mi[61] CW.
D = 11.7 +6.5i = 13.4mi[61o] = AD.
DA = 13.4[61+180] = 13.4mi[241o] CW = bearing from final point to port.
DA = 13.4[61+180] = 13.4mi[241o] CW = bearing from final point to port.
3 answers