Asked by Mariaaaaaaa
A vertical spring stretches 13 cm when a 2.3 kg block is hung from its end. (a) Calculate the spring constant. This block is then displaced an additional 3.2 cm downward and released from rest. Find the (b) period, (c) frequency, (d) amplitude, and (e) maximum speed of the resulting SHM
Answers
Answered by
bobpursley
k=2.3*9.8/.13 N/m
frequency = 1/2PI * sqrt(k/m)
period=1/f
amplitude=3.2cm
max speed:
1/2 m v^2=1/2 k (.032)^2 solve for v
frequency = 1/2PI * sqrt(k/m)
period=1/f
amplitude=3.2cm
max speed:
1/2 m v^2=1/2 k (.032)^2 solve for v
Answered by
Chris Zhang
a) Use hooke's law F=-kx
b) period=T=2PI*(m/k)^1/2
c) frequency=1/T=(k/m)^1/2*(1/2PI)
d) amplitude=x distance compressed/stretched (in this case 3.2 cm)
e) use conservation of energy to solve for speed: 1/2kx^2=1/2mv^2
b) period=T=2PI*(m/k)^1/2
c) frequency=1/T=(k/m)^1/2*(1/2PI)
d) amplitude=x distance compressed/stretched (in this case 3.2 cm)
e) use conservation of energy to solve for speed: 1/2kx^2=1/2mv^2
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