Question

A certain spring stretches 5.8cm when a load of 38N is suspended from it. How much will the spring stretch if 48N is suspended from it (and it doesn't reach its elastic limit)?

Answer 1

evidently the spring constant is

5.8cm/38N = .1526 cm/N

So, if 48N is suspended, the stretch is

48N*0.1526 cm/N = ? cm

Answer 2

7.3246

Answer 3

The length that a spring is stretched beyond its natural position is given by L = 2W where work, W, is k
in foot-pounds and k is a constant for the given spring. If a certain spring has a constant of 66.8, and the spring is to be stretched a length of 3.2 feet beyond its natural position, how much work will be necessary?