Asked by Rachel
A certain spring stretches 5.8cm when a load of 38N is suspended from it. How much will the spring stretch if 48N is suspended from it (and it doesn't reach its elastic limit)?
Answers
Answered by
Steve
evidently the spring constant is
5.8cm/38N = .1526 cm/N
So, if 48N is suspended, the stretch is
48N*0.1526 cm/N = ? cm
5.8cm/38N = .1526 cm/N
So, if 48N is suspended, the stretch is
48N*0.1526 cm/N = ? cm
Answered by
Anonymous
7.3246
Answered by
Anonymous
The length that a spring is stretched beyond its natural position is given by L = 2W where work, W, is k
in foot-pounds and k is a constant for the given spring. If a certain spring has a constant of 66.8, and the spring is to be stretched a length of 3.2 feet beyond its natural position, how much work will be necessary?
in foot-pounds and k is a constant for the given spring. If a certain spring has a constant of 66.8, and the spring is to be stretched a length of 3.2 feet beyond its natural position, how much work will be necessary?
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