weight = .010*9.8 = .098 Newtons
x = .05 m
k = 1.96 N/m
omega = sqrt (k/m) = 2 pi f
so
f = 2.23
T = 1/f = .45 seconds
A spring stretches 5.00 cm when a 10.00 g object is hung from it. The object is replaced with another object of mass 20.00 g that oscillates in simple harmonic motion.
a) Calculate the spring constant in N/m. Use 9.8 m/s2 for g.
b) Calculate the period of motion in seconds.
1 answer
1 answer