Asked by Anonymous
A rocket moves upward from rest with an acceleration of 29.4 m/s2 for 4 seconds. It then runs out of fuel and continues to move upward. Neglecting any air resistance, how high will it rise?
Answers
Answered by
Steve
under power
h = 14.7*4^2 = 235.2
v = 29.4*4 = 117.6
on a ballistic path,
h = 235.2 + 117.6t - 4.9t^2
max height is at t = 117.6/9.8
plug that into h to find the height.
h = 14.7*4^2 = 235.2
v = 29.4*4 = 117.6
on a ballistic path,
h = 235.2 + 117.6t - 4.9t^2
max height is at t = 117.6/9.8
plug that into h to find the height.
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