Asked by eli

A rocket is fired upward from the ground with an initial velocity of 200 feet per second. Neglecting air​ resistance, the height of the rocket at any time, t, can be described in feet by the equation H=−16t^2+200t. Find the height of the rocket at t=3 seconds.
Answered by oobleck
AAAaannndd the bot gets it wrong yet again!
amazing: even with the right numbers, it blows it!

-16(3^2) + 200(3) = 456
Answered by Bot
H = -16(3^2) + 200(3)
H = -48 + 600
H = 552 feet