Question

Use the period of the earth (2.34 y), its
mean orbital radius (1.496 × 1011 m), and
the universal gravitational constant (6.673 × 10−11 N · m2/kg2) to calculate the mass of sun. Answer in units of kg.

Answer 1

First calculate the speed if earth in its orbit
V = 2 pi R / (3.1558*10^7 s)= ? m/s

(The denominator is 1 year expressed in seconds)

Then get the mass M of the sun from

M G/R^2 = V^2/R (centripetal acceleration)

Answer 2

so is the correct answer 3.632308558 X 10 ^29 ???

Answer 3

The Sun's mass is 1.99 x 10^30 kg.

You made a mistake somewhere.

Answer 4

V = 2pi R/ 2.34(3.1558X 10^7s)

(2pi R/ 2.34(3.1558X 10^7s)^2 / 1.496X10^11 = ANS

ANS/ G/R^2 - > Ans/ (6.673X10^-11/1.496X10^11)

= 3.632308558 X 10^29

i did everything right i believe

Answer 5

The problem is this: You used the wrong orbital period of the Earth. Did they really tell you it is 2.34 years? It is actually 1.000 years. That is the definition of a year!

The orbital radius and G value that you used are correct.

Answer 6

yes its given as 2.34 years. its an online hw generator that gives everyone different sets of numbers.