Asked by Angie
First period: 85, 83, 74, 70, 88,95,89,72,90,83,77,91,98,89,82,84
Second period: 95,89,82,81,72,69,100,97,75,91,82,79,96,81,80,95,89,97,83,71
Mark is a student in the first period class. His score on the exam was 95%. Zoe is a student in the second period class, she also received a score of 95%. Are the two scores equivalent in relation to the scores in their respective classes?
A)suppose two students one from each class scored a 72 on the exam. What conclusion can you draw from this?
B)suppose a student had a score of 88 in 1st period class, and in 2nd period a student scored an 89, What conclusion can you draw after examining each students score?
Second period: 95,89,82,81,72,69,100,97,75,91,82,79,96,81,80,95,89,97,83,71
Mark is a student in the first period class. His score on the exam was 95%. Zoe is a student in the second period class, she also received a score of 95%. Are the two scores equivalent in relation to the scores in their respective classes?
A)suppose two students one from each class scored a 72 on the exam. What conclusion can you draw from this?
B)suppose a student had a score of 88 in 1st period class, and in 2nd period a student scored an 89, What conclusion can you draw after examining each students score?
Answers
Answered by
PsyDAG
The answer to the first question is yes.
For A and B, do the following for each period:
Find the mean first = sum of scores/number of scores
Subtract each of the scores from the mean and square each difference. Find the sum of these squares. Divide that by the number of scores to get variance.
Standard deviation = square root of variance
Z = (score-mean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions related to the Z scores.
I'll let you do the calculations.
For A and B, do the following for each period:
Find the mean first = sum of scores/number of scores
Subtract each of the scores from the mean and square each difference. Find the sum of these squares. Divide that by the number of scores to get variance.
Standard deviation = square root of variance
Z = (score-mean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions related to the Z scores.
I'll let you do the calculations.
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