Asked by jenny
Find the resultant of the following two displacements; 2.0 m 40 degrees 4.0 meters at 127 degrees. the angles are taken relative to the x-axis
Answers
Answered by
Damon
x component = 2 cos 40 + 4 cos 127
y component = 2 sin 40 + 4 sin 127
magnitude = sqrt(x^2+y^)
tan^-1 A = y/x
where A = angle from x axis
y component = 2 sin 40 + 4 sin 127
magnitude = sqrt(x^2+y^)
tan^-1 A = y/x
where A = angle from x axis
Answered by
Anonymous
2cos40+4cos127=-0.875
2sin40+4sin127=4.481
R=A+B
=-0.875+4.481
=3.6m
2sin40+4sin127=4.481
R=A+B
=-0.875+4.481
=3.6m
Answered by
Ta
answer
Answered by
Ta
answer
Answered by
Leah
lay out the
displacements to scale, tip to tail from the origin. Notice that all
angles are measured from the +x-axis. The resultant vector
points from starting point to end point as shown. We measure its
length on the scale diagram to find its magnitude, 4.6 m. Using a
protractor, we measure its angle θ to be 101°. The resultant
displacement is therefore 4.6 m at 101°
displacements to scale, tip to tail from the origin. Notice that all
angles are measured from the +x-axis. The resultant vector
points from starting point to end point as shown. We measure its
length on the scale diagram to find its magnitude, 4.6 m. Using a
protractor, we measure its angle θ to be 101°. The resultant
displacement is therefore 4.6 m at 101°
Answered by
NIKUZE
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Answered by
NIKUZE
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