Asked by Anonymous
Find out the resultant of two forces of 4N and 7N acting at an angle of 140°
Answers
Answered by
Damon
7 along x axis
4 at 40 degrees above y axis
Fx = 7 - 4 cos 40
Fy = 4 sin 40
|F| = sqrt (Fx^2 + Fy^2)
angle above x axis = tan^-1 (Fy/Fx)
4 at 40 degrees above y axis
Fx = 7 - 4 cos 40
Fy = 4 sin 40
|F| = sqrt (Fx^2 + Fy^2)
angle above x axis = tan^-1 (Fy/Fx)
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