Question
A snooker ball X of mass 0.3kg moving at 5m/s hit a stationary ball Y of mass 0.4kg and Y move at a velocity of 2m/s at angle to the initial direction of X. Find the velocity and direction of X after hitting
Answers
Damon
initial x momentum = .3*5
initial y momentum = 0
final x momentum = .3 Ux + .4(2)cosA
final y momentum = .3 Vx + .4(2)sinA
tanA = Vx/Ux = sin A / cos A
initial y momentum = 0
final x momentum = .3 Ux + .4(2)cosA
final y momentum = .3 Vx + .4(2)sinA
tanA = Vx/Ux = sin A / cos A