Asked by zach
A ball with a mass of 3.47 kg is rolling along at 17.4 m/s. If you apply a force of 52.2 N to it, how many seconds will it take to stop?
Answers
Answered by
Henry
F = M*a
a = F/M = 52.2/3.47 = 15 m/s^2
V = Vo - a*t
V = 0
Vo = 17.4 m/s
a = 15 m/s^2
t = ?
a = F/M = 52.2/3.47 = 15 m/s^2
V = Vo - a*t
V = 0
Vo = 17.4 m/s
a = 15 m/s^2
t = ?
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