Asked by Anonymous
A ball of mass .15 kg and a radius of .24 m is at the top of a 3.5 m tall hill with a 25 degree incline. What is the velocity of the ball as it reaches the bottom of the hill if it (a) rolls without slipping? (b)slips without rolling?
Answers
Answered by
drwls
The height of the hill H tells you the potential energy per unit mass, gH.
This equals the kinetic energy at the bottom in both cases.
In case (b), the KE per unit mass is just V squared.
In acase (a), rotational kinetic energy must be included, and the velocity will be less.
You will need to use the equation for the moment of inertia of a sphere.
We wll be happy to critique your work.
This equals the kinetic energy at the bottom in both cases.
In case (b), the KE per unit mass is just V squared.
In acase (a), rotational kinetic energy must be included, and the velocity will be less.
You will need to use the equation for the moment of inertia of a sphere.
We wll be happy to critique your work.
Answered by
Anonymous
Ok thanks! I think I figured out the equation..
you use mgh=1/2mv^2 + 1/2Iw^2 and solve for v. right?
you use mgh=1/2mv^2 + 1/2Iw^2 and solve for v. right?
Answered by
shakira
ion know.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.