Asked by Samuel
A snooker ball of mass 0.30kg slides on a frictional horizontal snooker board. Two snooker sticks strike the ball simultaneously.if the force F1 has a magnitude of 5N and points 20 South of East and the F2 has a magnitude of 8 N and points 60 north east. determine..
(I) the magnitude of the balls acceleration
(ii) the direction of the balls acceleration
(I) the magnitude of the balls acceleration
(ii) the direction of the balls acceleration
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Answered by
Anonymous
TYPOS?
A snooker ball of mass 0.30kg slides on a frictional (FRICTIONLESS???) horizontal snooker board. Two snooker sticks strike the ball simultaneously.if the force F1 has a magnitude of 5N and points 20 South of East and the F2 has a magnitude of 8 N and points 60 north (OF ???) east. determine.
Force East = Fe = 8 cos 60 + 5 cos 20 = 4+ 4.70 = 8.70
ForceNorth= Fn = 8 sin 60 - 5 sin 20 = 6.93 - 1.71 = 5.22
magnitude = sqrt ( 8.70^2 + 5.22^2)
tangent of angle north of east = Fn/Fe = 5.22/8.70
A snooker ball of mass 0.30kg slides on a frictional (FRICTIONLESS???) horizontal snooker board. Two snooker sticks strike the ball simultaneously.if the force F1 has a magnitude of 5N and points 20 South of East and the F2 has a magnitude of 8 N and points 60 north (OF ???) east. determine.
Force East = Fe = 8 cos 60 + 5 cos 20 = 4+ 4.70 = 8.70
ForceNorth= Fn = 8 sin 60 - 5 sin 20 = 6.93 - 1.71 = 5.22
magnitude = sqrt ( 8.70^2 + 5.22^2)
tangent of angle north of east = Fn/Fe = 5.22/8.70
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