Asked by scott
a slingshot launches a rock straight upward at 25 m/s, how high does the rock go, how long is it in the air, what is the velocity and the acceleration of the rock at its highest point
Answers
Answered by
Damon
g = 9.81 m/s^2
v = Vi - g t
at top v = 0
t = 25/9.81 seconds to top
double that for time in air
m g h = (1/2) m Vi^2
h = 625/(2*9.81)
v is 0 at top of course
a is -9.81 m/s^2 forever until it hits the mud.
v = Vi - g t
at top v = 0
t = 25/9.81 seconds to top
double that for time in air
m g h = (1/2) m Vi^2
h = 625/(2*9.81)
v is 0 at top of course
a is -9.81 m/s^2 forever until it hits the mud.
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