Asked by Isabelle
Arann launches a rock into the air such that it rises 20.0 m in the first third (time wise) of its ascent to maximum height.
Determine the rock's maximum height and launch speed.
Determine the time(s) at which the ball is at a height of 10m.
PLEASE HELP
Determine the rock's maximum height and launch speed.
Determine the time(s) at which the ball is at a height of 10m.
PLEASE HELP
Answers
Answered by
bobpursley
find the first third time
20=1/2 g t^2 + vi*t
or 4.9t^2-vi*t+20=0
and
vf=vi+gt
at the top 0=vi-9.8*3t
ok, then t=vi/(9.8*3)
Put that in the first equation, solve for vi.
Then, you can solve all else.
20=1/2 g t^2 + vi*t
or 4.9t^2-vi*t+20=0
and
vf=vi+gt
at the top 0=vi-9.8*3t
ok, then t=vi/(9.8*3)
Put that in the first equation, solve for vi.
Then, you can solve all else.
Answered by
Isabelle
^^ bobpursley
What formula did you use? Could you repost it using v1 and v2 as variables?
What formula did you use? Could you repost it using v1 and v2 as variables?
Answered by
bobpursley
vi is launch speed.
vf is the vertical velocity at the top,zero.
vf is the vertical velocity at the top,zero.
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