Asked by kyle
a person uses a slingshot to launch a rock upward with a velocity of 30m/s how long does it take to reach a height of 20m what maximum height does the rock reach, what is the velocity of the rock at this height, what is the velocity of the rock just before it lands
Answers
Answered by
bobpursley
upward motion:
h'=vi*t=1/2 * 9.8 t^2
h'=20, vi=30, solve for t using quadratic formula
now with t, v=vi-g*t, put vi=20, and t from above, and you have v.
Max height:
initial KE=final PE
1/2 m vi^2=mgh solve for h, the max height.
Velocity just before landing = negative of launch velocity.
h'=vi*t=1/2 * 9.8 t^2
h'=20, vi=30, solve for t using quadratic formula
now with t, v=vi-g*t, put vi=20, and t from above, and you have v.
Max height:
initial KE=final PE
1/2 m vi^2=mgh solve for h, the max height.
Velocity just before landing = negative of launch velocity.
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