A. t = 50 ft/s / 32.2 ft/s²
B. the velocity is zero at the peak
... so the average ascending velocity is 25 ft/s
... the displacement is 25 ft/s multiplied by the time from part A
C. the time is half of the time from part A
... the average velocity is (50 + 25)/2 ft/s
... the height is velocity times time
An arrow is shot straight up from the edge of a cliff with an initial velocity of 50 ft/s. Answer the following questions using English units. The acceleration due to gravity has a magnitude of 32.2 ft/s.
A. Find the time to reach the highest point.
B. Find the displacement at the highest point.
C. Find the height when the velocity is 25 ft/s.
2 answers
Can someone answer this step by step please!!!