Ask a New Question
Search
Asked by
Nimuel
The sides of two squares differ by 25cm while the sum of their areas is 2425cm. What is the length of the side of each square.
Please answer. Thank you
Answers
Answers
Answered by
Steve
sides: x and x+25
areas: x^2 and (x+25)^2
now finish it off.
Answered by
Nimuel
Sir, I know the answer--45&20
45-20=25
(45)^2+(20)^2=2425
(2025)+(400)=2425
but I don't know how to solve in step by step..
Answered by
Nimuel
Can I get the solution.. Thank you
Related Questions
Related
the sum of the squares pf two postive consecutive even integers is 41. Find the integers.
how many squares with sides that are 6 inches long and needed to cover a aquare with a side length o...
Squares with sides of length x are cut out of each corner of a rectangular piece of cardboard measur...
two sides of a rectangle differ by 3.5cm.find the dimentions of the rectangles if its perimeter is 6...
two squares have sides p cm and (p+5) cms. the sum of theirs squares is 625 sq.cm. the sides of the...
how many squares with sides that are 6 inches long are needed to cover a square with a side length o...
The sides of two squares differ by 25cm while the sum of their areas is 2425cm. What is the length o...
The sides of two squares are 4cm and 6cm. Find the ratio of their areas and their perimeters.
A figure has 8 sides; all sides meet at right angles. The left-most vertical side measures 31 meters...
the sum of the squares of two consecutive integers is 365. find the integers using the quadratic for...