Question
A box weighing 450 Newtons is pulled along a level floor at an angle of 30 degrees with the floor.If the force of the rope is 260 Newtons.What is the coefficient of sliding friction for the surface?
Answers
Scott
the horizontal pulling force is
... 260 cos(30º)
the vertical pulling force is
... 260 sin(30º)
the coefficient of sliding friction is
... [260 cos(30º)] /
... {450 - [260 sin(30º)]}
... 260 cos(30º)
the vertical pulling force is
... 260 sin(30º)
the coefficient of sliding friction is
... [260 cos(30º)] /
... {450 - [260 sin(30º)]}
Jeremiah
How to solve this problem in physics
K Dinesh
A 35 kg box is pulled along level floor at uniform speed by a rope which makes an angle of 30ᴼ with the floor. If the force on the rope is 80 N, what is the coefficient of friction?