Asked by amirah
a crate weighing 562 newtons is resting on an inclined plane 30 degress above the horizontal. Find the components of the weight forces that are parallel and perpendicular to the plane?
Answers
Answered by
Henry
Wc = mg = 562 N. = Weight of crate.
Fc = 562 N. @30 Deg. = Force of crate.
Fp = 562*sin30 = 281 N. = Force parallel to plane.
Fv = 562*cos30 = 487 N. = Force perpendicular to plane.
Fc = 562 N. @30 Deg. = Force of crate.
Fp = 562*sin30 = 281 N. = Force parallel to plane.
Fv = 562*cos30 = 487 N. = Force perpendicular to plane.
Answered by
mohammed
270-30=240
Answered by
luka
a crate weighing 562 newtons is resting on an inclined plane 30 degress above the horizontal. Find the components of the weight forces that are parallel and perpendicular to the plane?
Answered by
Maia
Fgx= 562cos(30.0)=486N
Fly= 562sin(30.0)=281
Tan-1(281 divides 486)
Fly= 562sin(30.0)=281
Tan-1(281 divides 486)
Answered by
Anonymous
yby
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