Asked by Liezel C. Cruz
A man weighing 500 newtons sits in swing suspended with two ropes if each rope makes an angle of 30 degree with the vertical, what is the tension in each rope?
Answers
Answered by
bobpursley
well, each rope is holding half the weight.
I see the following trinagle: cos30=1/2 weight/ tension
tension= 250N/cos30
check that diagram.
I see the following trinagle: cos30=1/2 weight/ tension
tension= 250N/cos30
check that diagram.
Answered by
Henry
T1*sin(90+30) + T2*sin60 = -500*sin270.
0.866T1 + 0.866T2 = 500.
T1 = T2. Replace T2 with T1.
0.866T1 + 0.866T1 = 500.
1.732T1 = 500.
T1 = 288.7 N. = T2.
0.866T1 + 0.866T2 = 500.
T1 = T2. Replace T2 with T1.
0.866T1 + 0.866T1 = 500.
1.732T1 = 500.
T1 = 288.7 N. = T2.
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