Asked by Jessie
An antifreeze solution is prepared containing 40.0 g of ethylene glycol (molar mass = 62.0 g/mol) in 60.0 g of water. Calculate the freezing point of this
solutions A.-20.1°C B.0.518°C C.20.1°C D.120.1°C
solutions A.-20.1°C B.0.518°C C.20.1°C D.120.1°C
Answers
Answered by
DrBob222
delta T = Kf*m
Find mols:
mols = grams ethyl/molar mass = ?
Find molality:
m = molality = mols/kg solvent
Plug m and Kf(1.86) into the delta T formula and solve for delta T. Then subtract that from zero to find the new freezing point.
Find mols:
mols = grams ethyl/molar mass = ?
Find molality:
m = molality = mols/kg solvent
Plug m and Kf(1.86) into the delta T formula and solve for delta T. Then subtract that from zero to find the new freezing point.
Answered by
Victoria Archila
-20.1⁰C
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