Question
an antifreeze solution is made by mixing ethylene glycol (density= 1116 kg/m^3) with water. suppose that the specific gravity of such a solution is 1.0730. assuming that the total volume of the solution is the sum of its parts, determine the volume percentage of ethylene glycol in the solution?
Answers
Let x be the volume fraction of ethylene glycol. Then 1-x is the volume fraction of water.
(1-x)*(1000) + x*1116 = 1.0730*1000 kg/m^3
x(116) = 73
x = 63%
(1-x)*(1000) + x*1116 = 1.0730*1000 kg/m^3
x(116) = 73
x = 63%
لي عوض حجم الماء ب x_1
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