Asked by josh

A stone is projected vertically upwards with a speed of 30ms from the top of a tower of height 50m. Neglecting air resistance determine the maximum height it reached from the ground.[g=10ms^2]
Answered by Damon
h = Hi + Vi t - 4.9 t^2

v = Vi - 9.81 t
when is v = 0 ? (the top)
t = 30/9.81 = 3.06 seconds coasting up to a stop

so
h = 50 + 30 (3.06) - 4.9 (3.06)^2
Answered by binta
a stone is projecting vertical upword with a speed of 30/s from the top of the tower of night 50m neglecting air resistance, the terming of the maximum hight to reach from the ground (g=10m/5²)
Answered by binta
a stone is projecting vertical upward with a speed of 30m/s from the top of the tower of hight 50m neglecting air resistance the terming of the maximum hight to reach from the ground (g=10/5²)
Answered by Patriarch
Answer please
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