Asked by SUBHAN
the acceleration of free fall on the moon is one sixth of that on earth. what would be the period on the moon of a simple pendulum which has a period of one second on the earth?
Answers
Answered by
bobpursley
period=2PI sqrt(g/length)
so the period on the moon will be
sqrt(1/6) that of the period on Earth.
so the period on the moon will be
sqrt(1/6) that of the period on Earth.
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