Asked by I attempted-HELP
A 600 N skydiver in free fall is accelerating at -7.6 m/s^2 rather than -9.8 m/s^2 because of the force of air resistance. How much drag force is acting on the skydiver?
a)58.2
b)65.3
c)61.4
d)40.2
I use the equation Σ(F)vertical-ma=0
To find m I did: 600/9.8 = 61.2
I end up getting Fdrag-600-(61.2)(-7.6)=0
I keep getting 135N which is not correct.
a)58.2
b)65.3
c)61.4
d)40.2
I use the equation Σ(F)vertical-ma=0
To find m I did: 600/9.8 = 61.2
I end up getting Fdrag-600-(61.2)(-7.6)=0
I keep getting 135N which is not correct.
Answers
Answered by
Damon
force down = 600
force up = Fd
600 - Fd = m a = 61.2 * 7.6
so Fd = 600 - 465
Fd = 135 N
so I agree with you
force up = Fd
600 - Fd = m a = 61.2 * 7.6
so Fd = 600 - 465
Fd = 135 N
so I agree with you
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