Asked by Josie

The free-fall acceleration on the surface of Jupiter is about two and one half times that on the surface of the Earth. The radius of Jupiter is about 11.0 RE (RE = Earth's radius = 6.4 106 m). Find the ratio of their average densities, ρJupiter/ρEarth.

12 years ago

Answered by AARON

1/6.4106

11 years ago

Answered by ALLAH

AKBAR

8 years ago

Answered by Alexander Vega Soto

5/22

4 years ago

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