Asked by Jem
an airplane flying due north with a speed relative to the ground of 300 km/hr. it then encounters a cross-wind that is directed due east. of the resultant speed of the airplane is now 302 km/hr, how fast is the cross wind?
Answers
Answered by
bobpursley
yes Pythagorean theorem
302^2=300^2 + V^2
302^2=300^2 + V^2
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