Asked by Jem
                an airplane flying due north with a speed relative to the ground of 300 km/hr. it then encounters a cross-wind that is directed due east. of the resultant speed of the airplane is now 302 km/hr, how fast is the cross wind?
            
            
        Answers
                    Answered by
            bobpursley
            
    yes Pythagorean theorem
302^2=300^2 + V^2
    
302^2=300^2 + V^2
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.