One does not normally give heading of a breeze. You specify the direction it comes FROM. However this seems to be specifying the direction it is GOING like it were a current so I will assume that.
north speed = Vn = 145 cos 84.5 + 24.6 cos 68.4
east Speed = Ve = 145 sin 84.5 + 24.6 sin 68.4
Speed = sqrt(Vn^2 + Ve^2)
course made good = C
tan C = Ve/Vn
an airplane is flying with an airspeed of 145 mph and a heading of 84.5 degrees. q wind of 24.6 omh is blowing at a heading of 68.4 degrees. find the ground speed and course of airplane
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