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Asked by Sarah

Evaluate the definite Integral
Integral [0 to pi/4] cos(2x)sec^2(pi/4 sin(2x))dx
9 years ago

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Answered by Steve
Let u = tan(π/4 sin(2x))
du = sec^2(π/4 sin(2x))*(π/4)(2cos(2x)) du

So, what you have is just ∫du with some constant factored out.
9 years ago
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Evaluate the definite Integral
Integral [0 to pi/4] cos(2x)sec^2(pi/4 sin(2x))dx

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