Asked by Sarah
use te fundamental theorem of calculus to evaluate the integral
Integral [0, pi/3] sin^2(x)dx
I'm confused on what F(x) should be
Integral [0, pi/3] sin^2(x)dx
I'm confused on what F(x) should be
Answers
Answered by
Steve
well, sin^2(x) = 1/2 (1-cos(2x))
that should be easy to integrate, right?
that should be easy to integrate, right?
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