Asked by Anon
Use the Fundamental Theorem of Calculus to find the derivative of
f(x)=∫[4,x^2]((1/4)t^2−1)^15 dt
f(x)=∫[4,x^2]((1/4)t^2−1)^15 dt
Answers
Answered by
Steve
that would be
((1/4)(x^2)^2−1)^15 * 2x
= 2x(x^4/4 - 1)^15
((1/4)(x^2)^2−1)^15 * 2x
= 2x(x^4/4 - 1)^15
Answered by
Reiny
To fully understand what Steve did, watch these two KhanAcademy clips
https://www.khanacademy.org/math/ap-calculus-ab/fundamental-theorem-of-calculus-ab/fundamental-theorem-of-calculus-tut-ab/v/fundamental-theorem-of-calculus
and
https://www.khanacademy.org/math/ap-calculus-ab/fundamental-theorem-of-calculus-ab/fundamental-theorem-of-calculus-tut-ab/v/applying-the-fundamental-theorem-of-calculus
special emphasis on the second of those two.
https://www.khanacademy.org/math/ap-calculus-ab/fundamental-theorem-of-calculus-ab/fundamental-theorem-of-calculus-tut-ab/v/fundamental-theorem-of-calculus
and
https://www.khanacademy.org/math/ap-calculus-ab/fundamental-theorem-of-calculus-ab/fundamental-theorem-of-calculus-tut-ab/v/applying-the-fundamental-theorem-of-calculus
special emphasis on the second of those two.
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