Asked by Nick
Use 2nd Fundamental Theorem of Calculus to find derivative of f(x) = integral of 2x^2 to x-5 of square root of Sin(t)dt.
Please help.
Please help.
Answers
Answered by
drwls
I'm sorry, but the integrand
"2x^2 to x-5 of square root of Sin(t)dt."
does not make sense.
In general, the derivative of an indefinite integral of a function is the function itself.
"2x^2 to x-5 of square root of Sin(t)dt."
does not make sense.
In general, the derivative of an indefinite integral of a function is the function itself.
Answered by
Nick
Ok, so if I change it to 2x^2 to x-5 of square root of Sin(x)dx, does it make sense?
We haven't done any examples with an x in both the top and bottom of the integral sign.
Thanks
We haven't done any examples with an x in both the top and bottom of the integral sign.
Thanks
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