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how many committee of five people can be chosen from 20 menand 12 women if exactly three men must be on each committee and at l...Asked by rose
how many committee of five people can be chosen from 20 men and 12 women if a) exactly three men must be on each committee
b) at least four women on each committee
b) at least four women on each committee
Answers
Answered by
Reiny
Ahh, I see you fixed the problem from your earlier post.
a) 20 men, 12 women, choose 5, with exactly 3 men
= C(20,3) x C(12,2)
= 2053(66)
= 135498
b) at least 4 women
---> 4 women or 5 women
= C(20,1) x C(12,4) + C(20,0) x C(12,5)
= 20(495) + 1(792)
= 10692
check my arithmetic
a) 20 men, 12 women, choose 5, with exactly 3 men
= C(20,3) x C(12,2)
= 2053(66)
= 135498
b) at least 4 women
---> 4 women or 5 women
= C(20,1) x C(12,4) + C(20,0) x C(12,5)
= 20(495) + 1(792)
= 10692
check my arithmetic
Answered by
Anonymous
a) 20 men, 12 women, choose 5, with exactly 3 men
= C(20,3) x C(12,2)
= 2053(66)
= 135498
b) at least 4 women
---> 4 women or 5 women
= C(20,1) x C(12,4) + C(20,0) x C(12,5)
= 20(495) + 1(792)
= 10692
= C(20,3) x C(12,2)
= 2053(66)
= 135498
b) at least 4 women
---> 4 women or 5 women
= C(20,1) x C(12,4) + C(20,0) x C(12,5)
= 20(495) + 1(792)
= 10692
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