Asked by rose

how many committee of five people can be chosen from 20 men and 12 women if a) exactly three men must be on each committee
b) at least four women on each committee

Answers

Answered by Reiny
Ahh, I see you fixed the problem from your earlier post.

a) 20 men, 12 women, choose 5, with exactly 3 men
= C(20,3) x C(12,2)
= 2053(66)
= 135498

b) at least 4 women
---> 4 women or 5 women

= C(20,1) x C(12,4) + C(20,0) x C(12,5)
= 20(495) + 1(792)
= 10692

check my arithmetic
Answered by Anonymous
a) 20 men, 12 women, choose 5, with exactly 3 men
= C(20,3) x C(12,2)
= 2053(66)
= 135498

b) at least 4 women
---> 4 women or 5 women

= C(20,1) x C(12,4) + C(20,0) x C(12,5)
= 20(495) + 1(792)
= 10692
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