Asked by Anonymous
If a committee of 3 is to be selected from a group of 15 students and 6 teachers, then the
number of different possible committees that have at most 1 teacher is...
I got 1260 by doing (6C1)(15C1)(14C1), but the correct answer is supposed to be 1085. How did they get this?
number of different possible committees that have at most 1 teacher is...
I got 1260 by doing (6C1)(15C1)(14C1), but the correct answer is supposed to be 1085. How did they get this?
Answers
Answered by
Reiny
At most 1 teacher ----> 1 teacher or no teacher
so C(6,1)*C(15,2) + C(6,0)*C(15,3)
= 6(105) + 1(455)
= 1085
so C(6,1)*C(15,2) + C(6,0)*C(15,3)
= 6(105) + 1(455)
= 1085
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