I would pick a number for the masses.
The convert masses to mols.
mols fraction X = molsX/total # of mols.
Post your work if you get stuck.
The convert masses to mols.
mols fraction X = molsX/total # of mols.
Post your work if you get stuck.
molar mass of benzene is =78.12 g/mol
molar mass of ethanol is =46.08g/mol
moles of C6H6=
5.00g/78.12g/mol=0.064004moles
moles of C2H5OH=
5.00 g/48.08g/mol=0.10851g/mol
so mole fraction of benzene should equal to=
0.064004mol/(0.064004+0.10851)=0.371mol
so the mole fraction of benzene is 0.371 mol
Is my approach to the problem correct?
Here's how you can do it:
1. Determine the molar mass of benzene (C6H6) and ethanol (C2H5OH):
- Molar mass of benzene (C6H6) = 12.01 g/mol (Carbon) × 6 + 1.01 g/mol (Hydrogen) × 6 = 78.11 g/mol
- Molar mass of ethanol (C2H5OH) = 12.01 g/mol (Carbon) × 2 + 1.01 g/mol (Hydrogen) × 6 + 16.00 g/mol (Oxygen) + 1.01 g/mol (Hydrogen) = 46.07 g/mol
2. Calculate the moles of benzene and ethanol:
- Moles of benzene = Mass of benzene / Molar mass of benzene
- Since equal masses of benzene and ethanol are used, the moles of benzene and ethanol will be the same.
3. Calculate the total moles of the mixture:
- Total moles of the mixture = Moles of benzene + Moles of ethanol
4. Calculate the mole fraction of benzene:
- Mole fraction of benzene = Moles of benzene / Total moles of the mixture
By following these steps, you can find the mole fraction of benzene in the mixture.