Asked by Temmick
A mixture is prepared using equal masses of two volatile liquid benzene, C6H6, and ethanol, C2H5OH. what is the mole fraction of benzene in this mixture?
for my answer I got 0.370 C6H6.
please help!
for my answer I got 0.370 C6H6.
please help!
Answers
Answered by
DrBob222
You're right for C6H6.
XC2H5OH is 1.00 - 0.370 = ?
XC2H5OH is 1.00 - 0.370 = ?
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