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A bullet leaves a rifle with a muzzle velocity of 521 m/s. While accelerating through the barrel of the rifle, the bullet moves...Asked by Anonymous
A bullet leaves a rifle with a muzzle velocity of 521 m/s .while accelerating through the barrel of the rifle , the bullet moves a distance of 0.840m.determine the acceleration if the bullet. (Assume a uniform acceletlration).
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Answered by
bobpursley
Vf^2=vi^2+2*acceleration*distance
solve for acceleration
solve for acceleration
Answered by
Gokul Gopakumar
I have 2 answers
1. u=521m/s
v=0
s= 0.840
now we use v^2=u^2+2as
0^2=521^2+2xax0.840
0=2771441+1.68a
1.68a=2771441
a= 2771441 by 1.68
a=161572.02
that's the first answer
2.velocity= distance by time
velocity = 521ms
distance = 0.840m
therefore time =0.840 by 521
=0.0016s
a=velocity by time
=521 by 0.0016 = 325625ms^2
that's my second answer
please help
1. u=521m/s
v=0
s= 0.840
now we use v^2=u^2+2as
0^2=521^2+2xax0.840
0=2771441+1.68a
1.68a=2771441
a= 2771441 by 1.68
a=161572.02
that's the first answer
2.velocity= distance by time
velocity = 521ms
distance = 0.840m
therefore time =0.840 by 521
=0.0016s
a=velocity by time
=521 by 0.0016 = 325625ms^2
that's my second answer
please help
Answered by
vanshu
this is not correct answer
Answered by
vanshu
I have been asked another question.
Answered by
vanshu
SORRY THIS IS RIGHT ANSWER.
Answered by
vanshu
THANKS FOR GIVING THIS ANSWER.
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