Asked by Jana
I'm not sure how to solve this equation algebraically:
38=20sin((2pi(t))/36)+22
I know the answer should be about 5.3 since I graphed it.
I can get as far as removing 22 from the right and then removing 20 from the right by dividing by 20. To get 0.8=sin((2pi(t))/36)
38=20sin((2pi(t))/36)+22
I know the answer should be about 5.3 since I graphed it.
I can get as far as removing 22 from the right and then removing 20 from the right by dividing by 20. To get 0.8=sin((2pi(t))/36)
Answers
Answered by
bobpursley
PI*t/18=arcsin.8
t=18/PI * arcsin(.8)
Your calculator is needed on that.
t=18/PI * arcsin(.8)
Your calculator is needed on that.
Answered by
Jana
thanks!
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