Asked by anonymous

An ice cube floats with 1/9 of its volume below the surface of water, calculate the density of ice.
















































































































Answers

Answered by Henry
Vb = Di/Dw * Vi = Vi/9.

Di/1000 * Vi = Vi/9,
Divide both sides by Vi:
Di/1000 = 1/9, Di = 1000/9 = 111.11 kg/m^3 = Density of the ice cube.


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