Asked by Joy
A paper cone has a base diameter of 8cm and a height of 3cm(a) use Pythagoras theorem to calculate it's slant height (b)if the cone is cut and opened out into the sector of a circle what is the angel of the sector
Answers
Answered by
Reiny
Make a sketch to see that r = 5, h = 3
then s^2 = 5^2 + 3^2 = 34
slant height = √34 cm
circumference of base of cone
= 2π(5) = 10π cm
This becomes the arc-length in a circle of circumference of 2π√34
let the angle of the sector be Ø
arc = rØ
10π = √34Ø
Ø = 10π/√34 radians
= appr 5.388 radians or appr 308.7°
then s^2 = 5^2 + 3^2 = 34
slant height = √34 cm
circumference of base of cone
= 2π(5) = 10π cm
This becomes the arc-length in a circle of circumference of 2π√34
let the angle of the sector be Ø
arc = rØ
10π = √34Ø
Ø = 10π/√34 radians
= appr 5.388 radians or appr 308.7°
Answered by
hussaina
calculate the curved surface area of the cone in terms of pi
Answered by
ucdfgh
a is 5cm b is 288 degree
Answered by
Esso
How is b=288?
Answered by
jiji
i don't know how to draw the sketch
Answered by
Esther
Abeg i no understand how una tey do this one ooo pls expantiate better o ti daru momi loju nsin biko na beg i de beg o mathematician
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