Asked by emily

8.
The half-life of a certain radioactive material is 71 hours. An initial amount of the material has a mass of 722 kg. Write an exponential function that models the decay of this material. Find how much radioactive material remains after 17 hours. Round your answer to the nearest thousandth.

A)y=1/2(1/722)^1/71x; 0.103 kg
B)y=722(1/2)^1/71x; 611.589 kg
C)y=2(1/722)^1/71x; 0.414 kg
D)y=722(1/2)^71x; 0 kg

I think it's B, can someone explain this to me?

Answers

Answered by Athenal
y=722(1/2)^1/71x
1/71x ???
I do not understand why this is so
Answered by Reiny
amount = 722 (1/2)^(t/71) , where t is in hours

so after 17 hours ....

amount = 722(1/2)^(17/71)
= 722(.847076...)
= 611.589 -------------> choice B
= appr 612 kg

It would be more logical to use t as a variable for time instead of x, but hehh, whatever turns them on.
Answered by satan
answers for the logarithmic quiz part 1
1.c
2.a
3.d
4.b
5.d
6.a
7.c
8.c
9.a
Answered by Skittles🍭🍬🍫
THX SO MUCH "satan"🖤
Answered by :)
thanks satan
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