Asked by Supansa
A cubical metal box has side L=10.34cm and mass m=150 g. How much mass must be placed inside the box if it is to float in water with its top at the surface?
Answers
Answered by
Damon
volume of water displaced = .1034^3 = .0011055 m^3
times density of water which is about 1000 kg/m^3
=1.106 kg of water displaced
Archimedes says we can float that much mass
.150 + m = 1.106
m = .956 kg = 956 grams
times density of water which is about 1000 kg/m^3
=1.106 kg of water displaced
Archimedes says we can float that much mass
.150 + m = 1.106
m = .956 kg = 956 grams
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