Question

a cubical block of side 2cm is lying on a table. if the density of the material of the cube is 10000kg/m^3. find the pressure exerted by the block on the table.
(g=10m/s^2).

Answer 1

Divide the block weight by the block's bottom area.
Pressure = (Rho)*g*a^3/a^2 = (rho)*g*a

a is the side length of the cube, in meters.
Rho is the density, in kg/m^ 3

They want you to use a wrong value for g.

Answer 2

side=2cm=0.02m
volume=0.000008m^3
density=10000kg/m^3
mass=vol*density
=0.000008*10000
=0.08kg
force=mg
=0.08*10
=0.8N
area=0.02*0.02
=0.0004m^2
pressure=force/area
=0.8/0.0004
=8000/4
=2000 pa

Answer 3

Why we have taken volume=0.000008 m^3