a metal cube of side 2 cm is totally submerged in waterof the density of the object is 5000kg/m^3 find the mass apparent and buoyant force

Answer 1

a. V = S^3 = (2*10^-2)^3 = 8*10^-6 m^3 = vol. of cube = vol. of water disp.
M = V*Do = 8*10^-6 * 5*10^3 = 0.04 kg. = mass of cube.

b. M = V*D = 8*10^-6 * 1000 = 8*10^-3 kg. = mass of water disp.
Buoyant force = M*g = 8*10^-3 * 9.8 = ---N.
Note: 1000 = density of water in kg/m^3.