Question
John bought 8 apples and 10 oranges for a total of $41.60. An orange cost 70 cents less than an apple. What was the total cost of the apples?
Answers
Bosnian
a = apples cost
o = orange cost
70 cents = 0.7 $
An orange cost 70 cents less than an apple.
This mean :
o = a - 0.7 $
Total cost = 41.6 $
8 a * 10 o = 41.6
8 a + 10 ( a - 0.7 ) = 41.6
8 a + 10 a - 7 = 41.6
18 a - 7 = 41.6 Add 7 to both sides
18 a - 7 + 7 = 41.6 + 7
18 a = 48.6 Divide both sides by 18
18 a / 18 = 48.6 / 18
a = 2.7 $
o = a - 0.7 $
o = 2.7 $ - 0.7 $ = 2 $
Apple cost 2.7 $.
Orange cost 2 $.
Proff :
8 * a + 10 * o = 8 * 2.7 + 10 * 2 = 21.6 + 20 = 41.6 $
o = orange cost
70 cents = 0.7 $
An orange cost 70 cents less than an apple.
This mean :
o = a - 0.7 $
Total cost = 41.6 $
8 a * 10 o = 41.6
8 a + 10 ( a - 0.7 ) = 41.6
8 a + 10 a - 7 = 41.6
18 a - 7 = 41.6 Add 7 to both sides
18 a - 7 + 7 = 41.6 + 7
18 a = 48.6 Divide both sides by 18
18 a / 18 = 48.6 / 18
a = 2.7 $
o = a - 0.7 $
o = 2.7 $ - 0.7 $ = 2 $
Apple cost 2.7 $.
Orange cost 2 $.
Proff :
8 * a + 10 * o = 8 * 2.7 + 10 * 2 = 21.6 + 20 = 41.6 $